Web将字符串添加到未知大小的数组C++ 我在C++中遇到了一些问题。 我想让用户以字符串的形式给程序一个输入，并一直这样做直到用户满意为止。我的输入工作正常，但当我想将字符串存储到数组中时，我遇到了一些问题。我必须为我的数组定义一个大小？有没有一种方法可以根据输入将输入存储在2或 ... WebJan 20, 2011 · As already others have answered (even better) roughly speaking, use getline () to read an entire line (i.e., a string terminating with \n) and cin>>var to read a number compatible with the type of var (integer, float, double etc.) or a single word. In this answer I want to emphasize a problem that arises when mixing the two methods. When you do:
How does cin read strings into an object of string class?
WebSep 13, 2013 · You can do it by using cin.ignore (). It would be something like this: string messageVar; cout << "Type your message: "; cin.ignore (); getline (cin, messageVar); This happens because the >> operator leaves a newline \n character in the input buffer. WebFeb 15, 2013 · Now you can cin string and character literals, and if the input is not an exact match, it acts just like any other type that failed to input correctly. Note that this only matches whitespace in string literals that aren't the first character. It's only three functions, all of which are brain-dead simple. Share Improve this answer Follow chained t shirt
Understanding the Concept of Cin Object in C++ for Beginners
WebOct 30, 2024 · By overloading operator>> and operator<<, this allows us to write std::cin >> a and std::cout << a in the above program. Similar to the Number class shown above, the std::string class also makes use of operator overloading. Webcin – Read String from user In the following example, we shall read a string from user using cin object. cin reads string until the occurrence of a space character. C++ Program #include using namespace std; int main () { string name; cout << "Enter a string : "; cin >> name; cout << "You entered a string : " << name << endl; } You can indeed use something like. std::string name; std::cin >> name; but the reading from the stream will stop on the first white space, so a name of the form "Bathsheba Everdene" will stop just after "Bathsheba". An alternative is. std::string name; std::getline (std::cin, name); which will read the whole line. haphazard disorganized